1/4" 10 dot challenge.

[ONE-TEN]

@NF1E Perhaps you can help young One-Ten understand that subtracting ONE bullet hole from a group measured center to center would not work?

THAT’S not what I was saying. It’s very clear that is not what I was saying I was speaking of Edge to Edge which is what you alluded to. Otherwise you never would have questioned.

I understood from the beginning what he meant. YOU questioned him, not me.

 

[ONE-TEN]

Give him a chance to engage his thinker instead of his keyboard. I think he does get it in the long run. You are right, when measuring center to center, the bullet diameter has nothing to do with the calculation. Whatta Hobby!

NF, who was the one confused and asking what you meant? It wasn’t me, was it? No.

 

[ONE-TEN]

YOUR words from post #20 Indian:

“Neither the top or bottom hole broke the center bullseye. Even if that bullseye were a .224 diameter, we'd have three distinct .224 measurements. 3 X .224 equals a .672 outside to outside group which would be a .428”

YOU said OUTSIDE to OUTSIDE! You were talking about Edge to Edge! NOT me chief. And now you are trying to turn it around. But, nope. Don’t do that.

 

[NF1E]

Sorry about causing the confusion. We all practice our disciplines and sometimes it's hard to explain when one is used to a particular set of rules. Whatta Hobby!

 

[IndianHead]

Sorry about causing the confusion. We all practice our disciplines and sometimes it's hard to explain when one is used to a particular set of rules. Whatta Hobby!

Nothing to be sorry about - you certainly did not create any confusion

 

[XUSNORDIE]

 

[ONE-TEN]

Sorry about causing the confusion. We all practice our disciplines and sometimes it's hard to explain when one is used to a particular set of rules. Whatta Hobby!

Nahh, alls well pard. None of this is any big deal. I don’t think to anyone.